Needing a little chemistry help

#1

VolsFan4Ever-11

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#1
Been a while since i've done this.. Never quite got this stuff either.

Indicate the mazimum number of electrons that can occupy each of the first three electron shells (energy levels) of an atom.

Would it be 2, 8, 18
 
#10
#10
On the one hand I applaud you for seeking assistance at the well of the Great VolNation.

On the other hand I would hope that you had other options when you get into molecular physics !

The fact that I knew it for a few months thirty years ago won't help you, my friend.

BTW - The whole college thing is worth it. Get the degree.
 
#11
#11
Yeah...it looks like others have given you good advice, but I'll shoot anyway.

It goes (note this isn't order of filling, because the 4th shell's s orbital would be filled before the 3rd shell's d orbital):

1s2 (2 s-orbital electrons in the 1st shell)
2s2 (2 s-orbital electrons in the 1st shell)
2p6 (6 p-oribital electrons in the 2nd shell)
3s2 (2 s-orbital electrons in the 3rd shell)
3p6 (6 p-orbital electrons in the 3rd shell)
3d10 (10 d-type electrons in the 3rd shell)

That makes:

1st shell: 2
2nd shell: 8
3rd shell: 18

Just use this:

bubbles_2.gif
 
#14
#14
Yeah...it looks like others have given you good advice, but I'll shoot anyway.

It goes (note this isn't order of filling, because the 4th shell's s orbital would be filled before the 3rd shell's d orbital):

1s2 (2 s-orbital electrons in the 1st shell)
2s2 (2 s-orbital electrons in the 1st shell)
2p6 (6 p-oribital electrons in the 2nd shell)
3s2 (2 s-orbital electrons in the 3rd shell)
3p6 (6 p-orbital electrons in the 3rd shell)
3d10 (10 d-type electrons in the 3rd shell)

That makes:

1st shell: 2
2nd shell: 8
3rd shell: 18

Just use this:

bubbles_2.gif

This post




















My head
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#15
#15
Screw chem, take physics, much more interesting and intuitive. JMO.
 
#17
#17
Yeah...it looks like others have given you good advice, but I'll shoot anyway.

It goes (note this isn't order of filling, because the 4th shell's s orbital would be filled before the 3rd shell's d orbital):

1s2 (2 s-orbital electrons in the 1st shell)
2s2 (2 s-orbital electrons in the 1st shell)
2p6 (6 p-oribital electrons in the 2nd shell)
3s2 (2 s-orbital electrons in the 3rd shell)
3p6 (6 p-orbital electrons in the 3rd shell)
3d10 (10 d-type electrons in the 3rd shell)

That makes:

1st shell: 2
2nd shell: 8
3rd shell: 18

Just use this:

bubbles_2.gif

I am happy to say that I do NOT miss doing this stuff.
 
#19
#19
Dear lord. I'll never survive that class. It's probably One of my biggest fears in life.
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#20
#20
Dear lord. I'll never survive that class. It's probably One of my biggest fears in life.
Posted via VolNation Mobile

Try not to let it intimidate you. Most of the class revolves around the same set of core principles. There is some memorization, but not as much as some other subjects. The rest is driven by understanding those core principles. If you just accept that it will make sense to you in time, you'll make it just fine.

What are you going to school for? You just left work for school, right?

Feel free to PM me questions anytime when this class comes around. And, zonetards, this is me being a nerd, not me hitting on kat.
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#24
#24
Raoult's Law maybe? Been 16 years since PChem and only 5 hrs sleep.

Haha...no, I just don't know how one sets out to prove laws of fundamental, observed proportionality mathematically. However, it can probably be done. I'm thinking that you would start with the kinetic theory of gases...but then again, can you prove a law using a theory? Raoult's law can be derived from equating fugacities, but since Henry's law involves an empirical constant, I'm not sure what the fundamental proof would look like.
 

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